48x^2+14x+1=0

Solution for 48x^2+14x+1=0 equation:

48x^2+14x+1=0

a = 48; b = 14; c = +1;
Δ = b2-4ac
Δ = 142-4·48·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*48}=\frac{-16}{96}
=-1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*48}=\frac{-12}{96}
=-1/8
$